Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

3. In Fig 7.33, $BD$ and $CE$ are altitudes of $\bigtriangleup ABC$ such that $BD= CE$ .

          (i) State the three pairs of equal parts in $\bigtriangleup CBD$ and $\bigtriangleup BCE$ .
          (ii) Is $\bigtriangleup CBD\cong \bigtriangleup BCE$ ? Why or why not?
          (iii) Is $\angle DCB= \angle EBC$ ? Why or why not?

Answers (1)

best_answer

i) Given, in $\bigtriangleup CBD$ and $\bigtriangleup BCE$ .

$BD= CE$

$\angle CEB=\angle BDC=90^o$

$\overline{ BC} = \overline{ CB}$

ii) So, By RHS Rule of congruency, we conclude:

$\bigtriangleup CBD\cong \bigtriangleup BCE$

iii) Since both the triangle are congruent, all parts of one triangle are equal to their corresponding part from another triangle.

So.

$\bigtriangleup CBD\cong \bigtriangleup BCE$ .

Posted by

Pankaj Sanodiya

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST 2024: NVS Class 6, 9 results out; documents required for admission

anam-khan

JNVST Class 6, 9 result 2024 likely tomorrow at navodaya.gov.in; cut-off marks, total seats

Latest Question