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  • (i)Two dice are thrown simultaneously. What is the probability that the sum of the numbers appearing on the dice is 7

Two dice are thrown simultaneously. What is the probability that the sum of the numbers appearing on the dice is

(i) 7?
(ii) a prime number?
(iii)  1?

Answers (1)

(i) Answer.  [1/6]
Solution. Probability ; probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one
Total cases after throwing of two dice = 36
Cases when total is 7 = (1, 6), (6, 1), (3, 4), (4, 3), (2, 5), (5, 2)
Total cases = 6
Let A be the event of getting total 7
Probability [p(A)]= \frac{Number\, of\, favourable\ cases }{Total\, number\, of\, cases}
Probability of getting sum 7 = \frac{6}{36}= \frac{1}{6}

(ii) Answer.  [5/12]
Solution.   Probability ; probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one
Total cases = 36
Prime number as a sum = (1, 1), (1, 2), (2, 1), (1, 4),
(4, 1), (2, 3), (3, 2), (1, 6), (6, 1), (3, 4), (4, 3), (2, 5), (5, 2), (6, 5), (5, 6)
Cases = 15
Probability  = \frac{Number\, of\, favourable\ cases }{Total\, number\, of\, cases}
Probability that sum is a prime number = \frac{15}{36}= \frac{5}{12}
(iii) Answer. [0]
Solution. Probability ; probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event. The value is expressed from zero to one
Total cases = 36
pairs from which we get sum 1 = 0
Cases = 0
Probability  = \frac{Number\, of\, favourable\ cases }{Total\, number\, of\, cases}
Probability of getting sum 1 = \frac{0}{36}= 0


 

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