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Middle term in the expansion of (a3 + ba)28is _________
Answers (1)
Given: (a3 + ba)28
Here, n = 28 (even)
Thus, there is only one middle term (28/2 + 1)th or 15th term.
Thus, the middle term, T15 = T14+1
= 28C14(a3)28-14(ba)14
= 28C14a42b14a14
= 28C14a56b14
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