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  • On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm and 45 cm, respectively. What is the minimum distance each should walk so that each can covers the same distance in complete steps

On a morning walk, three persons step off together and their steps measure 40 cm, 42 cm, and 45 cm, respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps?

Answers (1)

Step-length of first-person = 40 cm
  Step-length of second person = 42 cm
Step-length of third person = 45 cm
For finding the minimum distance which will be multiple of all step-lengths. we have to find the LCM of (40, 42, 45)

Prime factorization forms:
40 = 2 × 2 × 2 × 5 × 1
42 = 2 × 3 × 7 × 1
45 = 5 × 3 × 3 × 1
  LCM = 2 × 3 × 5 × 2 × 2 × 7 × 3 = 2520
Hence minimum distance is 2520 cm.
 

Posted by

infoexpert27

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