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  • Show that (4/3 m - 3/4 n )^2 + 2mn = 16/9 m^2 + 9/16 n^2

Q : 5         Show that.

                (iii)   (\frac{4}{3}m-\frac{3}{4}n)^2 +2mn=\frac{16}{9}m^2+\frac{9}{16}n^2

Answers (1)

best_answer

First we will solve the LHS :

             = (\frac{4}{3}m-\frac{3}{4}n)^2 +2mn = \frac{16}{9}m^2 - 2mn + \frac{9}{16}n^2 + 2mn

or                = \frac{16}{9}m^2 + \frac{9}{16}n^2

                  =  RHS

Posted by

Devendra Khairwa

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