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  • Show that if x square plus y square equal to 1, then the point x y square root of 1 minus x square minus y square is at a distance 1 unit from the origin.

Show that if x square plus y square equal to 1, then the point x y square root of 1 minus x square minus y square  is at a distance 1 unit from the origin.

Answers (1)

Given: x2 + y2 = 1

From origin to point \left ( x,y ,\sqrt{1 - x^{2}-y^{2}} \right ) )

Distance, d= \sqrt{x^{2}+y^{2}+ \left (\sqrt{1 - x^{2}-y^{2}} \right )^{2} }

                  = \sqrt{x^{2}+y^{2}+1 - x^{2}-y^{2}}=1

Posted by

Satyajeet Kumar

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