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Q : 4     Simplify. 

            (vi) (ab+bc)^2-2ab^2c

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We use identity
       (a+b)^{2} = a^{2} + 2ab + b^{2}
           In this a =  ab and b = bc
                              (ab+bc)^{2} = (ab)^{2} + 2(ab)(bc) + (bc)^{2}
                                                   = a^{2}b^{2} + 2ab^{2}c + b^{2}c^{2}
Now,    a^{2}b^{2} + 2ab^{2}c + b^{2}c^{2} - 2ab^{2}c
               =  a^{2}b^{2} + b^{2}c^{2}

Posted by

Gautam harsolia

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