2. Solve the following equations:
(a) 2(x + 4) = 12
(b) 3(n – 5) = 21
(c) 3(n – 5) = – 21
(d) – 4(2 + x) = 8
(e) 4(2 – x) = 8
(a) We have:
2(x + 4) = 12
Dividing both sides by 2, we have :
Transposing 4 to the RHS, we get :
Thus
(b) We have:
3(n – 5) = 21
Dividing both sides by 3, we have :
Transposing - 5 to the RHS, we get :
Thus
(c) We have :
3(n – 5) = – 21
Dividing both sides by 3, we have :
Transposing - 5 to the RHS, we get :
Thus
(d) We have :
– 4(2 + x) = 8
Dividing both sides by - 4, we have :
Transposing 2 to the RHS, we get :
Thus
(e) We have :
4(2 - x) = 8
Dividing both sides by 4, we have :
Transposing x to the RHS and 2 to the LHS , we get :
Thus