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  • Solve the following system of linear inequalities 3x+2y>24, 3x+y<15, x>4

Solve the following system of linear inequalities 3x+2y\geq 24, 3x+y\leq 15, x> 4

Answers (1)

Let us find the common region of all by plotting each inequality.

Given: 3x + 2y ≥ 24

Thus, for line,

3x + 2y = 24

x 0 8
y 12 0

Now, we know that (0,0) does not satisfy 3x + 2y ≥ 24

Thus, The region is away from the origin.

Now, 3x + y ≤ 15 … (given)

Thus, for line,

3x + y = 15

x 0 5
y 15 0

 

Now, here (0,0) satisfies 3x + y ≤ 15

Thus, the region is towards the origin.

Now, x ≥ 4 implies that the region is to the right of the line x = 4

Therefore, the above system has no common region as solution.
 

 

 

Posted by

infoexpert22

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