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Q2. The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 3 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.

Answers (1)

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Let the price of one  Bat be x and the price of one ball be y,

Now, According to the question,

3x+6y=3900.....(1)

x+3y=1300.....(2)

From(1) we have 

y=\frac{3900-3x}{6}

By putting different values of x, we get different corresponding values of y.So

X 100 300 -100
Y 600 500 700

Now, From (2), we have,

y=\frac{1300-x}{3}

By putting different values of x, we get different corresponding values of y.So

X 100 400 -200
Y 400 300 500

GRAPH:

Posted by

Pankaj Sanodiya

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