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The last two digits of the numbers 3400 are 01.

 

Answers (1)

The given statement is true.

Given: 3400 = (9)200

                     = (10 – 1)200

Thus, (10 – 1)200 = 200C0(10)200200C1(10)199 + ….. – 200C199(10)1 + 200C200(1)200

                                                      = 10200 – 200  x 10199 + …. – 10 x 200 + 1

Therefore, the last two digits will be 01.
 

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