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 The length of the latus rectum of the ellipse 3x+ y2 = 12 is
A. 4
B. 3
C. 8
D. 12

 

Answers (1)

Option (d) is correct.

Given ellipse is 3x2+y2=12

\frac{x^{2}}{4}+\frac{y^{2}}{12}=1

a2=4

a=2

b2=12

b=2\sqrt{3}

length of latus rectum=\frac{2a^{2}}{b}=\frac{4}{\sqrt{3}}

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