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  • The sum of first 16 terms of the AP: 10, 6, 2... is (A) –320 (B) 320 (C) –352 (D) –400

The sum of first 16 terms of the AP: 10, 6, 2... is

(A) –320

(B) 320

(C) –352

(D) –400

Answers (1)

\\$Given:AP=10,6,2$ \ldots $ here a\textsubscript{1}=firsttermandd=commondifference \\$ a\textsubscript{1} = 10, a\textsubscript{2}=6\\ d = a\textsubscript{2} - a\textsubscript{1 }\\ d =6 - 10\\ d = - 4\\ {{S}_{16}}=\frac{16}{2}(2a+(16-1)d) \\ = 8(2 \times 10 + 15 \times (-4))\\ = 8(20 - 60)\\ = 8 \times (-40) = - 320\\

Hence option A is the correct answer.

Posted by

infoexpert21

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