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Q.15.11 (c) The transverse displacement of a string (clamped at its both ends) is given by y(x,t)=0.06\; \sin (\frac{2\pi }{3}x)\cos (120\; \pi t)

where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3.0\times 10^{-2}\; kg.

Answer the following :

(c) Determine the tension in the string

Answers (1)

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The mass per unit length of the string is

\\\mu =\frac{M}{l}\\ \mu =\frac{3\times 10^{-2}}{1.5}\\ \mu =0.02\ kg\ m^{-1}

Speed of a transverse wave is given by

\\v=\sqrt{\frac{T}{\mu }}\\ T=\mu v^{2}\\ T=0.02\times (180)^{2}\\ T=648\ N

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