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The value of arg (x) when x < 0is:
A. 0
B. \frac{\pi}{2}
 
C. π
D. none of these

Answers (1)

The answer is the option (c).

\\ Let\: \: z= -x+0i \: \: and \: \: x<0 \\ |z|=\sqrt{(-1)^2+(0)^2 }=1,x<0

Since, the point (-x,0)lies on the negative side of the real axis , principal argument (z)

Hence, option c is correct

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