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  • The value of sqroot32+sqroot48 by sqroot8+sqroo12t is equal to : (A)sqroot 2 (B) 2 (C)4 (D)8

The value of \frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}} is equal to :

(A) \sqrt{2}
(B) 2
(C)4
(D) 8

Answers (1)

Answer.     [B]
Solution. 
\sqrt{32}+\sqrt{48}= \sqrt{16\times 2}+\sqrt{16\times3}= 4\left ( \sqrt{2}+\sqrt{3} \right )
\sqrt{8}+\sqrt{12}= \sqrt{4\times 2}+\sqrt{4\times3}= 2\left ( \sqrt{2}+\sqrt{3} \right )
\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}= \frac{4\left ( \sqrt{2}+\sqrt{3} \right )}{2\left ( \sqrt{2} \right )+\sqrt{3}}= 2
Hence, (B) is the correct option.

Posted by

infoexpert27

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