Q.8 Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.
Let the consecutive integers be x, x+1, x+2.
Now according to the question equation becomes,
2x + 3(x+1) + 4(x+2) = 74
or 2x + 3x + 3 + 4x + 8 = 74
or 9x + 11 = 74
Transposing 11 to the RHS we get,
9x = 74 - 11 = 63
Divinding both sides by 9.
Therefore required consecutive integers are 7, 8, 9.