Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Using elementary transformations, find the inverse of each of the matrices, if it exists in Exercises 1 to 17. [ 2 1 4 2]

Using elementary transformations, find the inverse of each of the matrices, if it exists
in Exercises 1 to 17.

    Q14.    \begin{bmatrix} 2 & 1\\ 4 & 2 \end{bmatrix}

Answers (1)

best_answer

A=\begin{bmatrix} 2 & 1\\ 4 & 2 \end{bmatrix}

                A=IA

\Rightarrow          \begin{bmatrix} 2 & 1\\ 4 & 2 \end{bmatrix} = \begin{bmatrix}1&0\\0&1 \end{bmatrix}A

             R_2\rightarrow \frac{R_2}{2}

\Rightarrow      \begin{bmatrix} 2 & 1\\ 2 & 1 \end{bmatrix} = \begin{bmatrix}1&0\\0&\frac{1}{2} \end{bmatrix}A

\Rightarrow          R_1\rightarrow R_1-R_2

\Rightarrow       \begin{bmatrix} 0 & 0\\ 2 & 1 \end{bmatrix} = \begin{bmatrix}1&\frac{-1}{2}\\0&\frac{1}{2} \end{bmatrix}A

Hence, we can see all upper values of matrix are zeros in L.H.S  so A^{-1} does not exist. 

Posted by

seema garhwal

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question