Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • Using (x+a)(x+b)=x^2+(a+b)x+ab, find 103×98

Q : 8           Using  (x+a)(x+b)=x^2+(a+b)x+ab , find 

                   (iii) 103 \times 98

Answers (1)

best_answer

We know,

(x+a)(x+b)=x^2+(a+b)x+ab

Using this formula,

103 \times 98 = (100 + 3)(100 - 2) = (100 + 3){100 + (-2)}

Here x =100, a = 3, b = -2

\therefore 103 \times 98  = 100^2+(3 + (-2))100+(3\times(-2))

= 10000+100-6

= 10094

Posted by

HARSH KANKARIA

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST 2025 Class 6 registration ends today; apply at navodaya.gov.in

Latest Question