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Values of k for which the quadratic equation 2x^{2}-kx+k=0  has equal roots is

(A) 0 only         (B) 4                (C) 8 only         (D) 0, 8

Answers (1)

(D) 0, 8

Here the given equation is 2x^{2}-kx+k=0

Compare with ax^{2}+bx+c=0 where a \neq 0  

 a=2,b=-k,c=k

It is given that roots are equal.

 Hence

  \\b^{2}-4ac=0\\ (-k)^{2}-4(2)(k)=0\\ k^{2}-8k=0\\ k(k-8)=0\\ k-8=0 \;\;\;\;\;\; k=0\\ k=8\\ k=0,8

 Hence for the value of k = 0, 8 the equation ax^{2}+bx+c=0  has equal roots.

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infoexpert24

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