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  • \wedge ^{0}_{m(NH_{4}OH)} is equal to ______________.

\wedge ^{0}_{m(NH_{4}OH)} is equal to ______________.

(i) \wedge ^{0}_{m(NH_{4}OH)} + \wedge ^{0}_{m(NH_{4}Cl)}- \wedge ^{0}_{(HCl)}

(ii) \wedge ^{0}_{m(NH_{4}Cl)} + \wedge ^{0}_{m(NaOH)}- \wedge ^{0}_{(NaCl)}

(iii) \wedge ^{0}_{m(NH_{4}Cl)} + \wedge ^{0}_{m(NaCl)}- \wedge ^{0}_{(NaOH)}

(iv) \wedge ^{0}_{m(NaOH)} + \wedge ^{0}_{m(NaCl)}- \wedge ^{0}_{(NH_{4}Cl)}

Answers (1)

The answer is the option (ii) NH_{4}Cl\rightleftharpoons NH_4^++Cl^-

                                               NaCl\rightleftharpoons Na^{+}+Cl^{-}

                                                NaOH\rightleftharpoons Na^{+}+OH^{-}

                                                NH_{4}OH\rightleftharpoons NH_{4}^{+}+OH^{-}

                               \wedge ^{0}_{m(NH_{4}Cl)} + \wedge ^{0}_{m(NaOH)}- \wedge ^{0}_{(NaCl)} 

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infoexpert23

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