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What will be the product obtained as a result of the following reaction and why?

 +H_{3}C-CH_{2}-CH_{2}Cl\overset{AlCl_{3}}{\rightarrow}

 

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When alkylation of Friedel-Crafts takes place with a higher alkyl halide in which primary carbocation is formed first and then converted into secondary carbocation, which is more stable. It is formed by rearrangement; therefore, the product is isopropyl benzene.

Primary carbocation- CH_{3}-CH_{2}-CH_{2}Cl+AlCl_{3}\rightarrow AlCl_{4}^{+}+CH_{3}-CH_{2}-CH_{2}^{+}

Secondary carbocation- CH_{3}-CH_{2}-CH_{2}^{+}\rightarrow CH_{3}-CH^{+}-CH_{3}

 

 +H_{3}C-CH_{2}-CH_{2}Cl\overset{AlCl_{3}}{\rightarrow} 

 

                                    

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