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What will happen during the electrolysis of an aqueous solution of CuSO_{4} by using platinum electrodes?

(i) Copper will deposit at the cathode.

(ii) Copper will deposit at the anode.

(iii) Oxygen will be released at anode.

(iv) Copper will dissolve at the anode.

Answers (1)

The answer is the option (i,iii)

CuSO_4\rightleftharpoons Cu^{2+}+SO_{4}^{2-}

H_{2}O\rightleftharpoons H^{+}+OH^{-}

At cathode : Cu^{2+}+2e^{-}\rightarrow Cu; E_{cell}^{0}=0.34 \; V

H^{+}+e^{-}\rightarrow\; \frac{1}{2} H_{2}; E_{cell}^{0}=0.00 \; V

At cathode, the reaction with higher E^{0} is preferred

At anode :2SO_{4}^{2-}-2e^{-}\rightarrow S_{2}O_{8}^{2-}; E_{cell}^{0}=1.96 V

2H_{2}O\rightarrow O_{2}+4H^{+}+4e^{-};E_{cell}^{0}=1.23V

At anode, the reaction with lower E^{o} is preferred.

 

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