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6. Write a digit in the blank space of each of the following numbers so that the number formed is divisible by 11 :
   (a) 92 __ 389             (b) 8 __ 9484.

Answers (5)

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(a) 92 __ 389

Sum of odd digits = 9 + (blank space) + 8 = 17 + blank space

Sum of even digits = 2 + 3 + 9 = 14

As we know,

The number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is divisible by 11.

If we make the sum of odd digits = 25

then we will have difference = 25 - 14 = 11

which is divisible by 11.

To make the sum of odd digits = 25,

 the number at black space would be 8.


 

 (b) 8 __ 9484

Sum of odd digits = 8 + 9 + 8  = 25

Sum of even digits = blank space + 4 + 4 = blank space + 8

The number is divisible by 11 if the difference between the sum of the digits at odd places and the sum of the digits at even places is divisible by 11.

If we make the sum of even digits = 14 then we will have difference = 25 - 14 = 11 which is divisible by 11.

To make the sum of even digits = 14,

the number at black space would be 6.

Posted by

Pankaj Sanodiya

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10_24

Posted by

Lakshmi

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Sum of add digits =9+.

Posted by

Sai vardhan

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90

Posted by

Hardik

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(A)

Sum of odd places are =9+X+8=17+X

Sum of even places are=2+3+9=14

Difference=17+X-14

                   =3+X

3+X=0

   X=-3

Since,(-3)is negative number 

So,we cannot take it 

Since 11 is the nearest multiple of 11

3+X=11

X=11-3

X=8

Posted by

Subham Debnath

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