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Write the Nernst equation for the cell reaction in the Daniel cell. How will the ECell be affected when the concentration of Zn^{2+} ions is increased?

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Daniel Cell :

Zn\; (s)\left |Zn^{2+} \right |\left | Cu^{2+} \right |Cu\; (s)

Anode :Zn(s)\rightarrow Zn^{2+}+2e^{-}

Cathode : Cu^{2+}+2e^{-}\rightarrow Cu (s)

Overall cell reaction : Zn (s)+Cu^{2+}\rightleftharpoons Zn^{2+}+Cu (s)

Q=\frac{[Zn^{2+}]}{[Cu^{2+}]}

E_{cell}=E_{cell}^{0}-\frac{0.059}{2}log \; \frac{[Zn^{2+}]}{[Cu^{2+}]}

Therefore, with increasing concentration of Zn^{2+}, the cell potential decreases.

 

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