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x and b are real numbers. If $b> 0$ and $\left |x \right |> b$ then

A. $x\epsilon \left ( -b,\infty \right )$

B. $x\epsilon \left ( -\infty,b \right )$

C. $x\epsilon \left ( -b,b \right )$

D. $x\epsilon \left ( -\infty .-b \right ) \upsilon \left ( b,\infty \right )$

Answers (1)

Given: |x|> b

Thus, there will be 2 cases,

x > b → x (b,∞) …….. (i)

& -x > b → x < -b

Thus, x $\epsilon$ (-∞, -b) ……… (ii)

Therefore,

x $\epsilon$ (-∞, -b) U (b,∞)

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