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  • Explain solution RD Sharma class 12 chapter 28 The Plane exercise Fill in the blank question 20 maths

Explain solution RD Sharma class 12 chapter 28 The Plane exercise Fill in the blank question 20 maths

Answers (1)

Answer:

 x - 3z = 10  is the required Cartesian equation

Hint:

 use direction cosine formula.

Given:

 P(1,0,-3)

Solution:

Assume direction cosine of the normal (a,b,c)

Equation of plane passing through (x,y,z)

\begin{aligned} &\Rightarrow a(x-x_{1})+b(y-y_1)+c(z-z_1)=0\\ \end{aligned}

Point  P(1,0,-3)

\begin{aligned} &\Rightarrow a(x-1)+b(y-0)+c(z-(-3))=0\\ \end{aligned}

Direction cosine of normal

(a,b,c) = (1 - 0, 0 - 0, -3 - 0)

(a,b,c) = (1,0,-3)

Equation of the plane

[(x - 1)+ 0 (y - 0) - 3 (2- (-3))]=0

x - 3z = 10

Posted by

Gurleen Kaur

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