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Explain solution RD Sharma class 12 chapter 28 The Plane exercise Fill in the blank question 4 maths

Answers (1)

Answer:

 \frac{X-1}{2}=\frac{Y-2}{3}=\frac{Z-3}{6}

Hint:

 Use bracket method

Given:

 (1,2,3)  and normal to the plane 2x - 3y + 6z = 11           

Solution:

Let the equation be

\frac{X-1}{2}=\frac{Y-2}{3}=\frac{Z-3}{6} = 0

\sqrt{(1)^{2}+\left ( \frac{3}{2} \right )+\left ( \frac{6}{3} \right )}

?  we will get normal equation

? 2x - 3y + 6z = 11

Posted by

Gurleen Kaur

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