Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Explain solution RD Sharma class 12 chapter Differentiation exercise 10.5 question 32 maths

Explain solution RD Sharma class 12 chapter Differentiation exercise 10.5 question 32 maths

Answers (1)

Answer: \frac{d y}{d x}=x^{\log x}\left[\frac{2 \log x}{x}\right]+(\log x)^{x}\left(\frac{1}{\log x}+\log (\log x)\right)

Hint: Differentiate the equation taking log on both sides

Given: y=x^{\log x}+(\log x)^{x}

Solution:  

Let’s assume y_{1}=x^{\log x} \text { and }

        \begin{aligned} &y_{2}=(\log x)^{x} \\\\ &\frac{d y}{d x}=\frac{d y_{1}}{d x}+\frac{d y_{2}}{d x} \end{aligned}

Now y_{1}=x^{\log x}

        \log y_{1}=\log x \cdot \log x

Diff w.r.t x

        \frac{1}{y_{1}} \times \frac{d y_{1}}{d x}=\left[\log x \cdot \frac{1}{x}+\log x \cdot \frac{1}{x}\right]

        \frac{d y_{1}}{d x}=x^{\log x}\left[\frac{2 \log x}{x}\right]        .............(1)

        \begin{aligned} &y_{2}=(\log x)^{x} \\\\ &\log y_{2}=x \log (\log x) \end{aligned}

Diff both sides w.r.t x

        \frac{1}{y_{2}} \frac{d y_{2}}{d x}=\left[x \cdot \frac{1}{\log x} \cdot \frac{1}{x} \cdot 1+\log (\log x)\right]

        \frac{d y_{2}}{d x}=(\log x)^{x}\left[\frac{1}{\log x}+\log (\log x)\right]       ...............(2)

        \begin{aligned} &\frac{d y}{d x}=\frac{d y_{1}}{d x}+\frac{d y_{2}}{d x} \\\\ &x^{\log x}\left[\frac{2 \log x}{x}\right]+(\log x)^{x}\left(\frac{1}{\log x}+\log (\log x)\right) \end{aligned}

 

Posted by

infoexpert26

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

PM Modi's Pariksha Pe Charcha 2025 to be held next month, registrations open till January 14
anam-khan

CBSE Board Exams 2025: Online portal for availing exemptions by CWSN students opens
anam-khan

Board Exams: States agree to equivalence; no question paper ‘jumbling’ from next year, says PARAKH CEO

Latest Question