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Explain solution RD Sharma class 12 chapter The Plane exercise 28.2 question 4 maths

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Answer:

Equation of plane is x+y+z=12

Hint:

Use the formula, \frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1,  where p, q \; \&\; r intercepts on co-ordinate axes.

Given:

Intercept on co-ordinate axes are equal.

Explanation:

It is given that,

Intercepts on co-ordinate axes are equal.

We know if  p, q \; \&\; r are intercepts on co-ordinate axes then

        \frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1

According to question, plane makes equal intercept on the co-ordinate axes

so, p=q=r

As the equation of plane is  \frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1

        \frac{x}{p}+\frac{y}{p}+\frac{z}{p}=1 \quad\quad\quad\quad(p=q=r)

        \Rightarrow x+y+z=p            ...........(i)

We have, the plane is passing through the points (2,4,6)

Plane passes through the points (2,4,6) so we substituting points in equation (i)

        \begin{aligned} &2+4+6=P \\ &\Rightarrow p=12 \\ &\therefore x+y+z=12 \end{aligned}

Hence, the required equation of plane is x+y+z=12

 

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