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Need Solution for R.D.Sharma Maths Class 12 Chapter 28 The Plane  Exercise 28.13 Question 19 Sub Question 2 Maths Textbook Solution.

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$$ \begin{aligned} &r 1(-3 i+3 j+3 k)=(i+j)(-3 i+3 j+3 k) \\ &r 1(-3 i+3 j+3 k)=-3+3=0 \\ &r 1=-3 x+3 y+3 z=0 \\ &\text { le. } x-y-z=0 \end{aligned}

Distance \; from \: (2,1,-4) \: is

\left(\frac{2-1-4}{\sqrt{1^{2}+1^{2}+1^{2}}}\right)=\frac{3}{\sqrt{3}}=\sqrt{3} \text {.units }

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