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  • Need solution for RD Sharma maths class 12 chapter The Plane exercise 28.2 question 2 sub question (ii)

Need solution for RD Sharma maths class 12 chapter The Plane exercise 28.2 question 2 sub question (ii)

Answers (1)

best_answer

Answer:

Intercepts form of the given equation is \frac{x}{3}+\frac{y}{4}+\frac{z}{-6}=1  & its intercepts on co-ordinate axes are 3,2  &  -6

Hint:

First divide the given equation by 6 then compare it with  \frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1,  where a, b  &  c intercepts on co-ordinate axes.

Given:

Equation of plane is 2x+3y-z=6        ...........(i)

Explanation:

Divide equation (i) by 6

        \begin{aligned} &\Rightarrow \frac{2 x+3 y-z}{6}=\frac{6}{6} \\\\ &\Rightarrow \frac{x}{3}+\frac{y}{2}-\frac{z}{6}=1 \end{aligned}

Compare above equation with  \frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1

Here, a=3, b=2 & c=-6

Thus, intercepts form is

        \frac{x}{3}+\frac{y}{2}+\frac{z}{(-6)}=1

& intercepts on co-ordinate axes are 3,2 & -6

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