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Please solve RD Sharma class 12 chapter The Plane exercise 28.2 question 1 maths textbook solution

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Answer:

The equation of plane whose intercepts on the co-ordinate axes are 2,-3,4 \; is\; 6x-4y+32=12

Hint:

The equation of plane whose intercept on the co-ordinate axes are p,q,r respectively given by

\frac{x}{p}+\frac{y}{q}+\frac{z}{r}=1

Given:

Intercepts on the co-ordinate axes are 2,-3,4.

Explanation:

It is given that

Intercepts on the co-ordinate axes are

2,-3,4.

So, the equation of required plane is

\begin{aligned} &\frac{x}{2}+\frac{y}{-3}+\frac{z}{4}=1 \\\\ &\frac{6 x-4 y+3 z}{12}=1 \\\\ &\Rightarrow 6 x-4 y+3 z=12 \end{aligned}

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