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Please solve RD Sharma class 12 chapter The Plane exercise 28.4 question 1 maths textbook solution

Answers (1)

Answer:

 \vec{r}.\hat{k}=3

Hint:

 You must know the rules of solving vector functions

Given:

Find the vector equation of a plane which is at a distance of 3 units from origin
and has k as the unit vector normal to it.

Solution:

We have

Normal vector,

\vec{n}=\hat{k}

Now,

\vec{n}=\frac{\vec{n}}{\left | \vec{n} \right |}=\frac{\hat{k}}{\left | \hat{k} \right |}=\frac{\hat{k}}{1}=\hat{k}

The equation of a plane  in normal form is

\vec{r}.\hat{n}=d \qquad \qquad \rightarrow (1)

[d= distance of plane from origin]
By putting

\vec{n}=\hat{k}
d = 3 units in (1) relation
We get,

\vec{r}.\hat{k}=3

This is the required vector equation

Posted by

Gurleen Kaur

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