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Please solve RD Sharma class 12 chapter The Plane exercise 28.8 question 1 maths textbook solution

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Answer:-  The answer of the given question is 2x-3y+z=7.

Hint:-  By find and putting the value of k

Given:-2x-3y+z=0 and point (1,-1,2)

Solution:-  Given equation of plane is 2x-3y+z=0                               … (i)

We know that equation of a plane parallel to given plane (i) is

                    2x-3y+z+k=0                         …(ii)

As given that, plane (ii) is passing through the point (1,-1,2) so it satisfy the plane (ii)

                    \begin{gathered} 2(1)-3(-1)+2+k=0 \\\\ k=-7 \end{gathered}

Put the value of k in equation (ii),

                     2x-3y+z-7=0

So, equation of the required plane is,  2x-3y+z=7                           

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