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Provide solution for RD Sharma maths class 12 chapter 28 The Plane exercise very short answer type question 14

Answers (1)

Answer:

 (\overrightarrow{r}-\overrightarrow{a}).(\overrightarrow{b}\times \overrightarrow{c})

Hint:

 Equation of plane in scalar product form

(\overrightarrow{r}-\overrightarrow{a}).\overrightarrow{n}=0

Given:

 \overrightarrow{r}=\overrightarrow{a}+\lambda \overrightarrow{b} \text { and }\overrightarrow{r}=\overrightarrow{a}+\mu \overrightarrow{c}

Solution:

\overrightarrow{r}=\overrightarrow{a}+\lambda \overrightarrow{b} \text { and }\overrightarrow{r}=\overrightarrow{a}+\mu \overrightarrow{c}

Plane will pass through \overrightarrow{a}.

 Normal of plane will be ⊥ to be both \overrightarrow{b}& \overrightarrow{c}

\overrightarrow{n}=\overrightarrow{b}\times \overrightarrow{c}

∴ General Eqn of the plane

(\overrightarrow{r}-\overrightarrow{a}).\overrightarrow{n}=0

\Rightarrow (\overrightarrow{r}-\overrightarrow{a}).(\overrightarrow{b}\times \overrightarrow{c})=0

Posted by

Gurleen Kaur

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