# NCERT Solutions for Class 8 Maths Chapter 14- Factorization

## NCERT Solutions for Class 8 Maths Chapter 14 Factorization

In this chapter, we study about the factorization of algebraic expressions and natural numbers. In this, there are 4 exercises. To better understand the topic factorization the NCERT Solutions for Class 8 Maths Chapter 14 Factorization are prepared and explained by the Maths experts. Factorization means Finding Factors and also it is a process in which we factorize algebraic expressions and write this expression as a product of its factors. These factors can be algebraic expressions, algebraic variable or numbers. Also, we all know that what is a factor, it is a number or expression which is a divisor of a particular number or expression. In NCERT Class 8 Maths Chapter 14 Factorization we are going to learn about Methods of common factors, Factorisation by regrouping terms, factorization using identities, factors of the form (x + a) ( x + b) and Division of Algebraic Expressions.

Example- if we take number 6. So, which are the numbers which exact divisors of 6 ( these are those number which can divide it completely so the remainder is zero). 6 = 2 times; 3 = 6 times; 1. Hence, 1, 2, 3, and 6 are the factors of 6. Expressions like 5xy, 3x (y + 1) are already in factor form. Their factors can be just predicted from them like factors of 5xy is 5, x, and y. But for the expressions like 2x + 6 or 2x + 2 + 5xy + 5y it is difficult to predict their factorisation. In Class 8 Chapter 14 Factorisation we will learn to develop systematic methods to factorize these types of expressions and find their factors. There are 4 exercises with 34 questions in NCERT Class 8 Maths Chapter 14 Factorisation.

## Important Topics of NCERT Class 8 Maths Chapter 14 Factorization-

• 14.1 Introduction
• 14.2 What is Factorization?
• 14.3 Division of Algebraic Expressions
• 14.4 Division of Algebraic Expressions Continued(Polynomial divide; Polynomial)
• 14.5 Can you Find the Error?

## Let's try to solve an example of NCERT Solutions for Class 8 Maths Chapter 14 Factorization

1. Simplify

$\frac{x^2-4}{x+2}$

This can be written as

$\frac{x^2-4}{x+2}=\frac{x-2\times2}{x+2}=\frac{x^2-2^2}{x+2}$

Now using the identity (a+b)(a-b) = a2-b2

(x+2)(x-2)=(x2-22)

therefor

$\frac{x^2-4}{x+2}=\frac{x-2\times2}{x+2}=\frac{x^2-2^2}{x+2}=\frac{(x+2)(x-2)}{x+2}=x-2$

## NCERT Solutions For Class 8 Maths: Chapter-wise

 Chapter-1 Rational Numbers Chapter-2 Linear Equations in One Variable Chapter-3 Understanding Quadrilaterals Chapter-4 Practical Geometry Chapter-5 Data Handling Chapter-6 Squares and Square Roots Chapter-7 Cubes and Cube Roots Chapter-8 Comparing Quantities Chapter-9 Algebraic Expressions and Identities Chapter-10 Visualizing Solid Shapes Chapter-11 Mensuration Chapter-12 Exponents and Powers Chapter-13 Direct and Inverse Proportions Chapter-15 Introduction to Graphs Chapter-16 Playing with Numbers