NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots

 

NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots: The calculation is the backbone of mathematics and if you want to have a good command over mathematics then you can’t neglect the calculation part. It's not just about calculating right but right calculation in minimal time using calculations technique. In this article, you will get CBSE NCERT solutions for class 8 maths chapter 7 cubes and cube roots. Cube is a well-known shape in geometry that comes with 3- dimensions that have all sides equal but here we will not discuss that cube. In this chapter, you are going to learn how cubes and cube roots are calculated for a given number. In solutions of NCERT for class 8 maths chapter 7 cubes and cube roots, you will get short tricks and techniques to crack the mathematical problems in minimal time. It will enhance your calculation skill which is very important for many competitive exams like SSC. 

  • Cube-

Cube means a number will be multiplied 3-times by itself. For example:- If we want to calculate the cube of 3 then the cube will be 3×3×3 = 27, similarly, a cube of 5 is 5×5×5=125.

  • Cube Root-

Cube root then cube root is just a reverse application of cube means when a number multiplied 3-times by itself then it will result in the cube and the root number of this result is called cube root. For example:- Cube of 3 = 3×3×3 which is equal to 27 and similarly in the reverse manner cube root of 27 is equal to 3. There is another way to understand this, Which number we should multiply 3 times by itself to gain 27, then the number which will strike in your mind will be 3.

Cube & Cube Root

There are 2 exercises with 7 questions in this chapter. You will get detailed explanations of all these questions in the CBSE NCERT solutions for class 8 maths chapter 7 cubes and cube roots. Check NCERT solutions for class 6 to 12 by clicking on the above link.

Topics of NCERT for Chapter 7 Cube and Cube Roots

7.1 Introduction

7.2 Cubes

7.2.1 Some interesting patterns

7.2.2 Smallest multiple that is a perfect cube

7.3 Cube Roots

7.3.1 Cube root through prime factorization method

7.3.2 Cube root of a cube number

NCERT solutions for class 8 maths chapter 7 cubes and cube roots topic 7.2 cubes 

Q(i) Find the one’s digit of the cube of each of the following numbers.

3331

Answer:

The detailed solution for the above-mentioned question is as follows,

Since the given number ends with 1, so the one’s digit of the cube of 3331 will be 1.

Q(ii) Find the one’s digit of the cube of each of the following numbers.

8888

Answer:

The detailed solution for the above-mentioned question is as follows

Since the given number ends with 8, so the one’s digit of the cube of 8888 will be 2.

Q(iii) Find the one's digit of the cube of each of the following numbers.

149

Answer:

The detailed solution for the above-mentioned question is as follows,

Since the given number has 9 at units place,  so the one’s digit of the cube of  149 will be 9.

Q(iv) Find the one’s digit of the cube of each of the following numbers.

 1005

Answer:

The detailed solution for the above-mentioned questions is as follows

Since the given number ends with 5, so one's digit of its cube will also end with 5.

Q(v) Find the one’s digit of the cube of each of the following numbers.

1024

Answer:

The solution to the above-mentioned question is as follows,

The given digit is ending with 4. So the one’s digit of the cube of 1024 will be 4.

Q(vi) Find the one’s digit of the cube of each of the following numbers.

77

Answer:

The detailed solution for above-mentioned question is as follows,

The given number is ending with 7, so its cube will end with 3.

Q(vii) Find the one’s digit of the cube of each of the following numbers.

 5022

Answer:

The detailed solution for the above-mentioned question is as follows,

Since the given number ends with 2, so its cube will end with 8.

Q(viii) Find the one’s digit of the cube of each of the following numbers.

 53

Answer:

The detailed solution for the above-mentioned question is as follows,

Since the given number has 3 at units place, so, its cube will end with 7.

Solutions of NCERT for class 8 maths chapter 7 cubes and cube roots topic 7.2.1 some interesting patterns

Q(a) Express the following numbers as the sum of odd numbers using the above pattern?

  6^{3}

Answer:

The detailed solution for the above mentioned question is as follows,

6^3 =  216  =>  31 + 33 + 35 + 37 + 39 + 41

Q(b) Express the following numbers as the sum of odd numbers using the above pattern?

 8^{3}

Answer:

The detailed solution for the above-mentioned question is as follows

8^3 =    512  =>  57 + 59 + 61 + 63 + 65 + 67 + 69 + 71

Q(c) Express the following numbers as the sum of odd numbers using the above pattern?

 7^{3}

Answer:

The detailed solution for the above-mentioned question is as follows

7= 43 + 45 + 47 + 49 + 51 + 53 + 55 

Q(iii). Consider the following pattern.

2^{3}-1^{3}=1+2\times 1\times 3

3^{3}-2^{3}=1+3\times2\times 3

4^{3}-3^{3}=1+4\times 3\times 3

Using the above pattern,find the value of the following.

  20^{3}-19^{3}

Answer:

The detailed solution for the above-written question is mentioned below,

20^{3}-19^{3} = 1 + 20\times19\times3 = 1 + 1140 = 1141

Q(iv) Consider the following pattern.

2^{3}-1^{3}=1+2\times 1\times 3

3^{3}-2^{3}=1+3\times2\times 3

4^{3}-3^{3}=1+4\times 3\times 3

Using the above pattern, find the value of the following.

  51^{3}-50^{3}

Answer:

The detailed solution for the above written question is mentioned below

51^{3}-50^{3} = 1 + 51\times50\times3 = 1 + 7650 = 7651

CBSE NCERT solutions for class 8 maths chapter 7 cubes and cube roots topic 7.2.1 subtopic cubes and their prime factors

Q. Which of the following are perfect cubes?

1. 400

2. 3375

3. 8000

4. 15625

5. 9000

6. 6859

7. 2025

8. 10648

Answer:

We will find it by prime factorization whether they make a pair of three prime numbers or not.

(1)  400 = 2\times2\times2\times2\times5\times5 .   So not a perfect cube.

(2)  3375 = 3\times3\times3\times5\times5\times5.  So it is a perfect cube.

(3)  8000 = 2\times2\times2\times2\times2\times2\times5\times5\times5.  So it is a perfect cube.

(4)  15625 = 5\times5\times5\times5\times5\times5.    So it is a perfect cube.

(5)  9000 = 2\times2\times2\times3\times3\times5\times5\times5.  So it is not a perfect cube.

(6)  6859 = 19\times19\times19.   So it is a perfect cube.

(7)  2025 = 3\times3\times3\times3\times5\times5.   So it is not a perfect cube.

(8)  10648 = 2\times2\times2\times11\times11\times11.  So it is a perfect cube.

CBSE NCERT solutions for class 8 maths chapter 7 cubes and cube roots topic 7.2.2 smallest multiple that is a perfect cube

Q. Check which of the following are perfect cubes.

(i) 2700

(ii) 16000

(iii) 64000

(iv) 900

(v) 125000

(vi) 36000

(vii) 21600

(viii) 10,000

(ix) 27000000

(x) 1000.

What pattern do you observe in these perfect cubes?

Answer:

The detailed solution for the above-written question is as follows

By prime factorization:

(i)  2700 = 2\times2\times3\times3\times3\times5\times5.      So it is not a perfect cube.

(ii)  16000 = 2\times2\times2\times2\times2\times2\times2\times5\times5\times5.   So it is not a perfect cube.

(iii)  64000 = 2\times2\times2\times2\times2\times2\times2\times2\times2\times5\times5\times5= 80\times80\times80.  So it is a perfect cube.

(iv)  900 = 2\times2\times3\times3\times5\times5.   So it is not a perfect cube.

(v)  125000 = 2\times2\times2\times5\times5\times5\times5\times5\times5.   So it is a perfect cube.

(vi) 36000 = 2\times2\times2\times2\times2\times3\times3\times5\times5\times5.  So it is not a perfect cube.

(vii) 21600 = 2\times2\times2\times2\times2\times3\times3\times3\times5\times5.  So it is not a perfect cube.

(viii) 10000 = 2\times2\times2\times2\times5\times5\times5\times5.  So it is not a perfect cube.

(ix)  27000000 = 2\times2\times2\times2\times2\times2\times3\times3\times3\times5\times5\times5\times5\times5\times5.   So it is a perfect cube.

(x)  1000 = 2\times2\times2\times5\times5\times5.  So it is a perfect cube.

We observe that the numbers above which are perfect cube have the number of zeros in multiple of 3.

NCERT solutions for class 8 maths chapter 7 cubes and cube roots-Exercise: 7.1

Q.1(i) Which of the following numbers are not perfect cubes?

216

Answer:

The detailed solution for the above-written question is as follows

By prime factorization of 216 gives: 

         216 = 2\times2\times2\times3\times3\times3

Since prime numbers are present in pairs of three, so the given number is a perfect cube.

Q.1(ii) Which of the following numbers are not perfect cubes?

 128

Answer:

We have 128.  By prime factorization we get,

         128 = 2\times2\times2\times2\times2\times2\times2

Since the prime numbers are not in pairs of three, so the given number is not a perfect cube.

Q.1(iii) Which of the following numbers are not perfect cubes?

1000

Answer:

The detailed solution for the above written is as follows

By prime factorization of 1000 we get : 

             1000 = 2\times2\times2\times5\times5\times5.

 So the given number is a perfect cube.

Q.1(iv) Which of the following numbers are not perfect cubes?

100

Answer:

The detailed solution for the above-written question is as follows

By prime factorization of 100 : 

    100 = 2\times2\times5\times5.

Since prime numbers are not in pair of three so given number is not a perfect cube.

Q.1(v) Which of the following numbers are not perfect cubes?

 46656

Answer:

We have 46656, by prime factorisation: 

      46656 = 2\times2\times2\times2\times2\times2\times3\times3\times3\times3\times3\times3.

Since prime numbers are in group of three. So the given number is a perfect cube.

Q.2 Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube.

(i) 243

(ii) 256

(iii) 72

(iv) 675

(v) 100

Answer:

This can be found by knowing about the prime factors of the number.

(i) 243 :     3\times3\times3\times3\times3.

                So it must be multiplied by 3.

(ii) 256 :    2\times2\times2\times2\times2\times2\times2\times2

                So the given number must be multiplied by 2 to make it a perfect cube.

(iii) 72 :    2\times2\times2\times3\times3

                So 72 must be multiplied by 3 to make it a perfect cube.

(iv) 675 :  3\times3\times3\times5\times5

                So it should be multiplied by 5.

(v) 100 :   2\times2\times5\times5

                So it should be multiplied by 10.

Q.3  Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube.

(i) 81

(ii) 128

(iii) 135

(iv) 192

(v) 704

Answer:

By prime factorization of given numbers : 

(i) 81 :      3\times3\times3\times3

              So given number needs to be divided by 3 to get a perfect cube.

(ii) 128 :    2\times2\times2\times2\times2\times2\times2.

              So the given number needs to be divided by 2 to get a perfect cube.

(iii) 135 :    3\times3\times3\times5

              So the given number needs to be divided by 5 to get a perfect cube.

(iv) 192 :    2\times2\times2\times2\times2\times2\times3

              So the given number needs to be divided by 3 to get a perfect cube.

(v)  704 :    2\times2\times2\times2\times2\times2\times11

              So the given number needs to be divided by 11 to get a perfect cube.

Q.4 Parikshit makes a cuboid of plasticine of sides 5\: cm,2\; cm,5\; cm. How many such cuboids will he need to form a cube?

Answer:

Volume of cuboid is  5\times2\times5 = 2\times5\times5 cm^3

To make it a cube need to make this a pefect cube number.

So we need  2\times2\times5 cuboids 

or      20 cuboids.  

Q. State true or false:

for any integer m,m^{2}< m^{3}. Why?

Answer:

The detailed solution for the above-written question is as follows.

False.

                m^2 < m^3 

or           0 < m^3 - m^2

or          m^3 - m^2>0

or         m^2\left ( m-1 \right )>0

Now put any number less than 1, we see that this relation doesn't hold.

So for m<1 this condition is not true.

NCERT solutions for class 8 maths chapter 7 cubes and cube roots-Exercise: 7.2

Q.1(i) Find the cube root of each of the following numbers by prime factorisation method.

64

Answer:

The detailed solution for the above-written question is as follows

Prime factorization of 64 gives :

       64 = 2\times2\times2\times2\times2\times2

So its cube root is  2\times2  = 4

Q.1(ii) Find the cube root of each of the following numbers by prime factorisation method.

 512

Answer:

By prime factorisation of 512 :

       512 = 2\times2\times2\times2\times2\times2\times2\times2\times2

So its cube root is  2\times2\times2 = 8

Q.1(iii) Find the cube root of each of the following numbers by prime factorisation method.

10648

Answer:

The detailed solution for the above-written question is as follows

Prime factorization of 10648 gives : 

          10648 = 2\times2\times2\times11\times11\times11

So its cube root is 22.

Q.1(iv) Find the cube root of each of the following numbers by prime factorisation method.

 27000

Answer:

The detailed solution for the above-written question is as follows

By prime factorization method, we get :

     27000 = 2\times2\times2\times3\times3\times3\times5\times5\times5

 So its cube root is 30.

Q.1(v) Find the cube root of each of the following numbers by prime factorisation method.

15625

Answer:

The detailed solution for the above-written question is as follows

By prime factorization:

     15625 = 5\times5\times5\times5\times5\times5

So its cube root is 25.

Q.1(vi) Find the cube root of each of the following numbers by prime factorisation method.

13824

Answer:

The detailed solution for the above-written question is as follows

By prime factorization:

                13824 = 2\times2\times2\times2\times2\times2\times2\times2\times2\times3\times3\times3

So its cube root is 24.

Q.1(vii) Find the cube root of each of the following numbers by prime factorisation method.

 110592

Answer:

The detailed solution for the above-written question is as follows

By prime factorization:    

                110592 = 2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times2\times3\times3\times3

So its cube root is 2\times2\times2\times2\times3 = 48.

Q.1(viii) Find the cube root of each of the following numbers by prime factorisation method.

 46656

Answer:

The detailed solution for the above-written question is as follows

By prime factorization, we get :

                 46656 = 2\times2\times2\times2\times2\times2\times3\times3\times3\times3\times3\times3

So its cube root is 2\times2\times3\times3   =   36.

Q.1(ix) Find the cube root of each of the following numbers by prime factorisation method.

175616

Answer:

The detailed solution for the above-written question is as follows

By prime factorization we get : 

                    175616 = 2\times2\times2\times2\times2\times2\times2\times2\times2\times7\times7\times7

So its cube root is   2\times2\times2\times7  =  56.

Q.1(x) Find the cube root of each of the following numbers by prime factorisation method.

 91125

Answer:

The detailed solution for the above-written question is as follows

By prime factorization, we get : 

                91125 = 3\times3\times3\times3\times3\times3\times5\times5\times5

So its cube root is   3\times3\times5   =   45.

Q2. State true or false.

(i)  Cube of any odd number is even.

(ii)  A perfect cube does not end with two zeros.

(iii)  If square of a number ends with 5, then its cube ends with 25.

(iv)  There is no perfect cube which ends with 8

(v)  The cube of a two digit number may be a three digit number.

(vi)  The cube of a two digit number may have seven or more digits.

(vii)  The cube of a single digit number may be a single digit number.

Answer:

(i) False.  Cube of an odd number can never be even.

(ii) True.  Perfect cube number ends with zeros multiple of three.

(iii) False. We can say only about units place.

(iv) False. Cube of numbers which ends with 2 end with 8.

(v) False. Can never be.

(vi) False. Can never be. It can be proved by taking examples.

(vii) True. e.g. 1,2 

Q.3 You are told that 1,331 is a perfect cube. Can you guess without factorisation what
is its cube root? Similarly, guess the cube roots of

4913,

12167,

32768.

Answer:

We have  1331.

Divide number in two parts: The first part is 1 and second is 331.

  Since the given number is ending with 1 so the last digit of cube root will be 1.

In the first part, we have 1.

So  1^3 = 1

By estimation, the cube root of 1331 is 11.

Similarly for all other parts.

4913:-    First part is 4 and the second part is 913.

              The number is ending with 3 so its cube root will have 7 at units place.

              In the first part, the nearest cube root is 1.

               So the cube root of 4913 is 17.

12167:-    First part is 12 and the second part is 167.

                The number is ending with 7 so its cube root will have 3 at units place.

                 In the first part, the nearest cube root is 2.

               So the cube root of 12167 is 23.

32768:-   First part is 32 and the second part is 768.

                The number is ending with 8, so its cube root will have 2 at units place.

                In the first part, the nearest cube root is  3.

                So the cube root of 32768 is 32.

NCERT solutions for class 8 maths: Chapter-wise

Chapter -1

NCERT solutions for class 8 maths chapter 1 Rational Numbers

Chapter -2 

Solutions of NCERT for class 8 maths chapter 2 Linear Equations in One Variable

Chapter-3

CBSE NCERT solutions for class 8 maths chapter 3 Understanding Quadrilaterals

Chapter-4

NCERT solutions for class 8 maths chapter 4 Practical Geometry

Chapter-5

Solutions of NCERT for class 8 maths chapter 5 Data Handling

Chapter-6

CBSE NCERT solutions for class 8 maths chapter 6 Squares and Square Roots

Chapter-7

NCERT solutions for class 8 maths chapter 7 Cubes and Cube Roots

Chapter-8

Solutions of NCERT for class 8 maths chapter 8 Comparing Quantities

Chapter-9

NCERT solutions for class 8 maths chapter 9 Algebraic Expressions and Identities

Chapter-10

CBSE NCERT solutions for class 8 maths chapter 10 Visualizing Solid Shapes

Chapter-11

NCERT solutions for class 8 maths chapter 11 Mensuration

Chapter-12

NCERT Solutions for class 8 maths chapter 12 Exponents and Powers

Chapter-13

CBSE NCERT solutions for class 8 maths chapter 13 Direct and Inverse Proportions

Chapter-14

NCERT solutions for class 8 maths chapter 14 Factorization

Chapter-15

Solutions of NCERT for class 8 maths chapter 15 Introduction to Graphs

Chapter-16

CBSE NCERT solutions for class 8 maths chapter 16 Playing with Numbers

NCERT solutions for class 8: Subject-wise

Benefits of NCERT solutions for class 8 maths chapter 7 cubes and cube roots-

  • These solutions are prepared in a very simple language which can be understood very easily
  • You will learn some short tricks, so you can solve the problem in minimal time.
  • You should try to solve every problem of the textbook including examples and practice questions given after every topic. If are having difficulty while solving, these solutions are hare to help you. 
  • In CBSE NCERT solutions for class 8 maths chapter 7 cubes and cube roots, you will get solutions to practice question which is given after every topic also.  
  • It will help you with homework as well

Happy Reading!!!

 

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