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6. A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?

Distance travelled by vehicle in 2.4 litres of petrol = 43.2 km

Distance travelled by vehicle in 1 litre of petrol:

$=\frac{43.2}{2.4}=\frac{432}{24}\times\frac{10}{10}=18$

Hence Distance travelled by vehicle in 1 litre is 18 km.

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Pankaj Sanodiya

#2.7

5. Find:

$(i)\; 7\div 3.5$ $(ii)\; 36\div 0.2$ $(iii)\; 3.25\div 0.5$ $(iv)\; 30.94\div 0.7$

$(v)\; 0.5\div 0.25$ $(vi)\; 7.75\div 0.25$ $(vii)\; 76.5\div 0.15$ $(viii)\; 37.8\div 1.4$

$(ix)\; 2.73\div 1.3$

As we know, while dividing decimal, we first express the decimal in term of fraction and then divides it,

And

Dividing by a number is equivalent to multiplying by the reciprocal of that number.

$(i)\; 7\div 3.5$

$\; 7\div 3.5=7\div \frac{35}{10}=7\times\frac{10}{35}=\frac{70}{35}=2$

$(ii)\; 36\div 0.2$

$\; 36\div 0.2=36\div\frac{2}{10}=36\times\frac{10}{2}=180$

$(iii)\; 3.25\div 0.5$

$\; 3.25\div 0.5=\frac{325}{100}\div\frac{5}{10}=\frac{325}{100}\times\frac{10}{5}=\frac{65}{10}=6.5$

$(iv)\; 30.94\div 0.7$

$\; 30.94\div 0.7=\frac{3094}{100}\div\frac{7}{10}=\frac{3094}{100}\times\frac{10}{7}=\frac{442}{10}=44.2$

$(v)\; 0.5\div 0.25$

$\; 0.5\div 0.25=\frac{5}{10}\div\frac{25}{100}=\frac{5}{10}\times\frac{100}{25}=\frac{10}{5}=2$

$(vi)\; 7.75\div 0.25$

$\; 7.75\div 0.25=\frac{775}{100}\div\frac{25}{100}=\frac{775}{100}\times\frac{100}{25}=31$

$(vii)\; 76.5\div 0.15$

$\; 76.5\div 0.15=\frac{765}{10}\div\frac{15}{100}=\frac{765}{10}\times\frac{100}{15}=510$

$(viii)\; 37.8\div 1.4$

$\; 37.8\div 1.4=\frac{378}{10}\div\frac{14}{10}=\frac{378}{10}\times\frac{10}{14}=27$

$(ix)\; 2.73\div 1.3$

$\; 2.73\div 1.3=\frac{273}{100}\div\frac{13}{10}=\frac{273}{100}\times\frac{10}{13}=\frac{21}{10}=2.1$

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Pankaj Sanodiya

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#2.7

4.    Find:

             $(i)\; 7.9\div 1000$          $(ii)\; 26.3\div 1000$             $(iii)\; 38.53\div 1000$           $(iv)\; 128.9\div 1000$

           $(v)\; 0.5\div 1000$

As we know, while dividing a decimal number by 1000 we shift the decimal to left by 3 digits, So

$(i)\; 7.9\div 1000$

$\; 7.9\div 1000=0.0079$

$(ii)\; 26.3\div 1000$

$\; 26.3\div 1000=0.0263$

$(iii)\; 38.53\div 1000$

$\; 38.53\div 1000=0.03853$

$(iv)\; 128.9\div 1000$

$\; 128.9\div 1000=0.1289$

$(v)\; 0.5\div 1000$

$\; 0.5\div 1000=0.0005$

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Pankaj Sanodiya

#2.7

3. Find:

$(i)\; 2.7\div 100$ $(ii)\; 0.3\div 100$ $(iii)\; 0.78\div 100$ $(iv)\; 432.6\div 100$

$(v)\; 23.6\div 100$ $(vi)\; 98.53\div 100$

As we know while dividing a decimal number by 100, the decimal point gets shifted to left by two digits.

$(i)\; 2.7\div 100$

$\; 2.7\div 100=0.027$

$(ii)\; 0.3\div 100$

$\; 0.3\div 100=0.003$

$(iii)\; 0.78\div 100$

$\; 0.78\div 100=0.0078$

$(iv)\; 432.6\div 100$

$\; 432.6\div 100=4.326$

$(v)\; 23.6\div 100$

$\; 23.6\div 100=0.236$

$(vi)\; 98.53\div 100$

$\; 98.53\div 100=0.9853$

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Pankaj Sanodiya

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#2.7

2. Find:

$(i)\; 4.8\div 10$ $(ii)\; 52.5\div 10$ $(iii)\; 0.7\div 10$ $(iv)\; 33.1\div 10$

$(v)\; 272.23\div 10$ $(vi)\; 0.56\div 10$ $(vii)\; 3.97\div 10$

As we know, When we divide a decimal number by 10, the decimal point gets shifted by one digit in the left.

$(i)\; 4.8\div 10$

$\; 4.8\div 10=0.48$

$(ii)\; 52.5\div 10$

$\; 52.5\div 10=5.25$

$(iii)\; 0.7\div 10$

$\; 0.7\div 10=0.07$

$(iv)\; 33.1\div 10$

$\; 33.1\div 10=3.31$

$(v)\; 272.23\div 10$

$\; 272.23\div 10=27.223$

$(vi)\; 0.56\div 10$

$\; 0.56\div 10=0.056$

$(vii)\; 3.97\div 10$

$\; 3.97\div 10=0.397$

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Pankaj Sanodiya

#2.7

1.   Find:

             $(i)\; 0.4\div 2$            $(ii)\; 0.35\div 5$          $(iii)\; 2.48\div 4$              $(iv)\; 65.4\div 6$

             $(v)\; 651.2\div 4$      $(vi)\; 14.49\div 7$       $(vii)\; 3.96\div 4$            $(viii)\; 0.80\div 5$

As we know, while dividing decimal, we first express the decimal in term of fraction and then divides it,

And

Dividing by a number is equivalent to multiplying by the reciprocal of that number. So

$(i)\; 0.4\div 2$

$\; 0.4\div 2=\frac{4}{10}\div2=\frac{4}{10}\times\frac{1}{2}=\frac{2}{10}=\frac{1}{5}$

$(ii)\; 0.35\div 5$

$\; 0.35\div 5=\frac{35}{100}\div5=\frac{35}{100}\times\frac{1}{5}=\frac{7}{100}=0.07$

$(iii)\; 2.48\div 4$

$\; 2.48\div 4=\frac{248}{100}\div4=\frac{248}{100}\times\frac{1}{4}=\frac{62}{100}=0.62$

$(iv)\; 65.4\div 6$

$\; 65.4\div 6=\frac{654}{100}\div6=\frac{654}{100}\times\frac{1}{6}=\frac{109}{100}=1.09$

$(v)\; 651.2\div 4$

$\; 651.2\div 4=\frac{6512}{10}\div4=\frac{6512}{10}\times\frac{1}{4}=\frac{1628}{10}=162.8$

$(vi)\; 14.49\div 7$

$\; 14.49\div 7=\frac{1449}{100}\div7=\frac{1449}{100}\times\frac{1}{7}=\frac{207}{100}=2.07$

$(vii)\; 3.96\div 4$

$\; 3.96\div 4=\frac{396}{100}\div4=\frac{396}{100}\times\frac{1}{4}=\frac{99}{100}=0.99$

$(viii)\; 0.80\div 5$

$\; 0.80\div 5=\frac{80}{100}\div5=\frac{80}{100}\times\frac{1}{5}=\frac{16}{100}=0.16$

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Get Answers to all your Questions

All Questions

6. A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?

Posted by

Pankaj Sanodiya

5. Find:

Posted by

Pankaj Sanodiya

Crack CUET with india's "Best Teachers"

4. Find:

Posted by

Pankaj Sanodiya

3. Find:

Posted by

Pankaj Sanodiya

JEE Main high-scoring chapters and topics

2. Find:

5. Find:

$(i)\; 7\div 3.5$ $(ii)\; 36\div 0.2$ $(iii)\; 3.25\div 0.5$ $(iv)\; 30.94\div 0.7$

$(v)\; 0.5\div 0.25$ $(vi)\; 7.75\div 0.25$ $(vii)\; 76.5\div 0.15$ $(viii)\; 37.8\div 1.4$

$(ix)\; 2.73\div 1.3$

4. Find:

$(i)\; 7.9\div 1000$ $(ii)\; 26.3\div 1000$ $(iii)\; 38.53\div 1000$ $(iv)\; 128.9\div 1000$

$(v)\; 0.5\div 1000$

3. Find:

$(i)\; 2.7\div 100$ $(ii)\; 0.3\div 100$ $(iii)\; 0.78\div 100$ $(iv)\; 432.6\div 100$

$(v)\; 23.6\div 100$ $(vi)\; 98.53\div 100$

2. Find:

$(i)\; 4.8\div 10$ $(ii)\; 52.5\div 10$ $(iii)\; 0.7\div 10$ $(iv)\; 33.1\div 10$

$(v)\; 272.23\div 10$ $(vi)\; 0.56\div 10$ $(vii)\; 3.97\div 10$

1. Find:

$(i)\; 0.4\div 2$ $(ii)\; 0.35\div 5$ $(iii)\; 2.48\div 4$ $(iv)\; 65.4\div 6$

$(v)\; 651.2\div 4$ $(vi)\; 14.49\div 7$ $(vii)\; 3.96\div 4$ $(viii)\; 0.80\div 5$