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A bag contains 5 red and 3 blue balls. If 3 balls are drawn at random without replacement the probability of getting exactly one red ball is
A. 45/196
B. 135/392
C. 15/56
D. 15/29

 

Answers (1)

The Probability of getting exactly one red ball is

P(R).P(B).P(B) + P(B).P(R).P(B) + P(B).P(B).P(R)

\\ =\frac{5}{8} \cdot \frac{3}{7} \cdot \frac{2}{6}+\frac{3}{8} \cdot \frac{5}{7} \cdot \frac{2}{6}+\frac{3}{8} \cdot \frac{2}{7} \cdot \frac{5}{6} \\ =\frac{15}{56}

Option C is correct.

Posted by

infoexpert22

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