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A primary amine, \text {RNH}_{2} can be reacted with \text {CH}_{3}-\text {X} to get secondary amine, \text {RNHCH}_{3}, but the only disadvantage is that 3^{o} amine and quaternary ammonium salts are also obtained as side products. Can you suggest a method where \text {RNH}_{2} forms only 2^{o} amine?

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\\\text {R}-\text {NH}_{2}+\text {CHCl}_{3}+\text {3KOH}\rightarrow \text {R}-\text {NC}\xrightarrow[\text {(Reduction)}]{\text {H}_{2}/\text {Pd}}\text {R}-\text {NH}-\text {CH}_{3}\\\; 1^{o}\text {Amine}\; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \text {Alkyl isocyanide} \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; 2^{o}\text {Amine}

Carbylamine reaction is shown by 1^{o} amine only which result in the replacement of two hydrogen atoms attached to N atom of -\text {NH}_{2}  group by one carbon atom to form isocyanide. On catalytic reduction, the isocyanide will give a secondary amine with one methyl group.

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