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2.36    2\times 10 ^{8} atoms of carbon are arranged side by side. Calculate the radius of carbon atom if the length of this arrangement is 2.4 cm.

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The arrangement length is given which is 2.4\ cm = 2.4\times10^{-2} m.

and the number of atoms of carbon which are arranged in this length is given 2\times10^8.

Let the radius of carbon atom be 'r' then,

(2r)\times(2\times10^8) = 2.4\times10^{-2} m

\Rightarrow r = \frac{2.4\times10^{-2}m}{(2\times10^8)\times2} = 0.060\times10^{-9}m  or  r = 0.060\ nm

Hence the radius of carbon atom is r = 0.060\ nm.

 

Posted by

Divya Prakash Singh

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