6 boys and 6 girls sit in a row at random. The probability that all the girls sit together is
A. 1/432
B. 12/431
C. 1/132
D. none of these
Let us consider group 1 where all girls sit together,
Thus,
G |
G |
G |
G |
G |
G |
6 BOYS |
Total persons = 1 + 6
= 7
Now, total no. of arrangements in row of 7 = 7!
Also, the ways in which girls interchange their seats is 6!
Probability = no. of favorable outcomes/ total no. of outcomes
= 6! 7! / 12!
= 6 x 5 x 4 x 3 x 2 x 1 x 7! / 12 x 11 x 10 x 9 x 8 x 7!
= 6 x 5 x 4 x 3 x 2 / 12 x 11 x 10 x 9 x 8
= 1 / 2 x 11 x 2 x 3 x 2
= 1 / 132
Thus, option C is the correct answer.