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  • A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57μm. Calculate the rate of emission of quanta per second.

2.11    A 25 watt bulb emits monochromatic yellow light of wavelength of 0.57μm. Calculate the rate of emission of quanta per second.

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Given that the light is monochromatic yellow of wavelength \lambda = 0.57\mu m.

Hence the energy emitted by the bulb will be:

E = \frac{hc}{\lambda} = \frac{6.626\times10^{-34}Js\times 3.0\times10^{8}m/s}{0.57\times10^{-6} m} = 3.48\times10^{-19 }J

Therefore, the number of photons emitted per second:

\frac{25Js^{-1}}{3.48\times10^{-19}J} = 7.18\times10^{19}

 

Posted by

Divya Prakash Singh

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