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  • A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (ii) P(not B)

17.(ii)  A and B are events such that P(A) \small =0.42,  P(B) \small =0.48 and  P(A and B) \small =0.16. Determine (ii) P(not B) 

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Given, P(A) = 0.42,  P(B) = 0.48 and  P(A and B) = 0.16

(ii) P(not\ B) = P(B') = 1 - P(B)

\implies P(not\ B) = 1 - 0.48 = 0.52

Therefore, P(not B) = 0.52

Posted by

HARSH KANKARIA

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