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  • A and B are events such that P(A) = 0.42, P(B) = 0.48 and P(A and B) = 0.16. Determine (iii) P(A or B)

17(iii) A and B are events such that  P(A) \small =0.42 , P(B) \small =0.48  and P(A and B) \small =0.16. Determine (iii)  P(A or B) 

Answers (1)

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Given, P(A) = 0.42,  P(B) = 0.48 and  P(A and B) = 0.16

(iii) We know,

  P(A \cup B) = P(A)+ P(B) - P(A \cap B)

\implies P(A \cup B) = 0.42 + 0.48 - 0.16 = 0.9 - 0.16

 = 0.74

Posted by

HARSH KANKARIA

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