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  • A brown ring is formed in the ring test for NO_{3} – ion.It is due to the formation of (i)[ Fe( H_{2}O)5 ( NO) ]^{2+} (ii) FeSO_{4}.NO_{2}

A brown ring is formed in the ring test for NO_{3}^{-} ion. It is due to the formation of

(i) \left [ Fe\left ( H_{2}O \right )_{5} \left ( NO \right ) \right ]^{2+}

(ii) FeSO_{4}.NO_{2}

(iii)​ \left [Fe\left ( H_{2}O \right )_{4} \left ( NO \right )_{2} \right]^{2+}

(iv) FeSO_{4}.HNO_{3}

Answers (1)

The answer is the option (i). On addition of freshly prepared solution of FeSO_{4}  in a NO_{3}^{-} ion containing solution, a brown coloured complex is formed. This is also known as brown ring test of nitrate.

NO_{3}^{-}+3Fe^{2+}+4H^{+}\rightarrow NO+3Fe^{3+}+2H_{2}O

\left [ Fe\left ( H_{2}O \right )_{6} \right ]^{2+}+NO\rightarrow \left [ Fe\left ( H_{2}O \right )_{5}\left ( NO \right ) \right ]^{2+}\left ( Brown\; ring \right )+H_{2}O

Hence, 2 moles of NO are produced from 2 moles of ammonia.

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