Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path?

Q. 13.     A circular flower bed is surrounded by a path 4\; m wide. The diameter of the flower bed is 66\; m. What is the area of this path? (\pi =3.14)

               

Answers (1)

best_answer

It is given that the diameter of the flower bed is 66\; m

Therefore, r = \frac{66}{2} = 33 \ m

Now, we know that

Area of the circle (A) = \pi r^2

\Rightarrow \pi r^2= 3.14 \times(33)^2= 3419.46\ m^2                             -(i)

Now, radius of outer circle with radius(r ') = 33 + 4 = 37 cm is 

\Rightarrow \pi r'^2= 3.14 \times(37)^2= 4298.66 \ m^2                               -(ii)                                       

The area of the path is equation (ii) - (i)

\Rightarrow 4298.66-3419.46 = 879.2 \ m^2

Therefore, the area of the path is  879.2 \ m^2

Posted by

Gautam harsolia

View full answer

Similar Questions

Trending Articles/News

anam-khan

JNVST Class 6 admit card 2025 out at navodaya.gov.in; exam in 2 phases
anam-khan

NVS LEST 2025 application correction deadline today at navodaya.gov.in; editable fields
anam-khan

NVS 2025 application correction window for Class 9, 11 admissions opens at navodaya.gov.in

Latest Question