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  • A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500 degree C and then placed on a large ice block.

Q. 11.13 A copper block of mass 2.5 \; kg is heated in a furnace to a temperature of 500^{\circ}C and then placed on a large ice block. What is the maximum amount of ice that can melt? (Specific heat of copper =0.39\; j\; g^{-1}K^{-1}; heat of fusion of water =335\; j\; g^{-1}).

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Mass of copper block m = 2.5 kg

Initial Temperature of the copper block, T1 = 500 oC

Final Temperature of Copper block, T2 = 0 oC

Specific heat of copper, c = 0.39 J g-1 K-1

Thermal Energy released by the copper block is \Delta Q

\\\Delta Q=mc\Delta T\\ \Delta Q=2.5\times 10^{3}\times 0.39\times 500\\ \Delta Q=487500\ J

Latent heat of fusion of water, L = 335 j g-1

Amount of ice that can melt is

\\w=\frac{\Delta Q}{L}\\ w=\frac{487500}{335}\\ w=1455.22g

1.455 kg of ice can melt using the heat released by the copper block.

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