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  • A die is thrown 6 times. If 'getting an odd number' is a success ,what is the probability of (i) 5 successes?

Q. 1   A die is thrown 6 times. If ‘getting an odd number’ is a success, what is the probability of

            (i) 5 successes?

Answers (1)

best_answer

X be the number of success of getting an odd number.

P(probability\, of\, getting\, odd\, number)=\frac{3}{6}=\frac{1}{2}

\therefore \, \, \, \, q=1-P=1-\frac{1}{2}=\frac{1}{2}

X has a binomial distribution.

\therefore \, \, \, \, P(X=x)=^nC_n_-_x.q^{n-x}.p^x

       P(X=x)=^6C_6_-_x.(\frac{1}{2})^{6-x} . (\frac{1}{2})^{x}

       P(X=x)=^6C_6_-_x.(\frac{1}{2})^{6}

    P(5\, \, \, success) =P(x=5)

                                 = ^6C_5 .(\frac{1}{2})^6

                                = 6 .(\frac{1}{64})

                               = \frac{3}{32}

Posted by

seema garhwal

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